How do I catch a MongoSecurityException?

Question

I\'m trying to validate the login details of a specific user here.

This just won\'t work. I have no idea why, it never reaches the catch block even though there is a

Answer 1

You cannot catch MongoSecurityException as it is thrown in a background thread.

You can wait for a MongoTimeoutException to handle 'synchronously':

  MongoClientOptions clientOptions = new MongoClientOptions.Builder().serverSelectionTimeout(500).build();
    mongoClient = new MongoClient(serverAddress, Collections.singletonList(credential), clientOptions);
    try {
        String address = mongoClient.getConnectPoint();
        System.out.println(address);
    }catch (Throwable e){
        System.out.println(e);
    }

Or you can implement a ServerListener and handle asynchronously

{ 
MongoClientOptions clientOptions = new MongoClientOptions.Builder().addServerListener(this).build();
mongoClient = new MongoClient(host1, Collections.singletonList(credential), clientOptions);
}

@Override
public void serverDescriptionChanged(ServerDescriptionChangedEvent event) {
    Throwable exception = event.getNewDescription().getException();
    handle(exception);
}