Expected expression before ']' token?

Question

I have the following line which sends the arguments args[] and length to a method called largest.

  printf(\"Largest is: %         


        

Answer 1

 printf("Largest is: %d \n", largest(args, length));

just remove the '[]', because args is a pointer and that's what the function is expecting.

Answer 2

You probably just want the pointer of the array, so pass in largest(args, length) instead.

Answer 3

because you need to place an integer between the operator square brakets, or otherwise don't specify the square brackets :

printf("Largest is: %d \n", largest(&args[0], length));

or

printf("Largest is: %d \n", largest(args, length));

Keep in mind that args[0] is the same as *(args + 0) but args[] will give an error because it needs a number to sum ...

Answer 4

You can't pass an array like that. You have to pass the pointer to the array (first item):

printf("Largest is: %d \n", largest(args, length));