I am attempting to do some calculations in Excel on numbers that include long decimals.
However, Excel doesn\'t seem to let me populate the cells with the numbers I woul
This has to do with the number precision Excel can handle. I noticed that I can show the .00000000030000000000 portion just fine if you remove the integer part. Maybe you could have a separate column for your integer, do your calculations on the decimal part and afterwards add the integer part again. You can check the wiki regarding this issue - by adding the 600,000, you are essentially adding 6e5+3e-8, which Excel has to work with cummulative bit depth. Numeric precision in Microsoft Excel
Excel only stores 15 significant figures for numbers. Any figures beyond that automatically get rounded, regardless of number format.
Setting the cell to Text format first will store the number as a string with as many digits as you want, but Excel can't perform any calculations on it.
However, VBA can do calculations with Decimal type variables which can store up to 29 significant figures.
If you first store the values as text in Excel (setting the cell number format to Text before entering the values), you can create a User Defined Function in VBA to read the string values, convert them to Decimal values, perform your calculations and then return a string with the full precision calculated.
For example:
Function PrecisionSum(ra As Range) As String
'Declare variables holding high precision Decimal values as Variants
Dim decSum As Variant
'This loop will sum values from all cells in input range
For Each raCell In ra
'Read values from input cells, converting the strings to Decimals using CDec function
decSum = decSum + CDec(raCell.Value)
Next raCell
'Return calculated result as a String
PrecisionSum = Format(decSum, "0.00000000000000000000")
End Function
You'll need to write functions to do the operations that you desire.
Note that you'll still be limited by the accuracy of any functions you use in VBA. For example, the SQR function to return the square root of a number only returns a number with Double precision regardless of the precision of the input.
You could try to use exponential (Scientific) notation?