Reqular expression for 11 digit phone number with 09 prefix

Question

I am trying to write a regular expression to handle phone number which starts with \"0\" followed by \"9\" and 9 digits which can be anything within 0-9.

-(BOOL)         


        

Answer 1

Using a NSString method:

- (BOOL)validateAlphabets: (NSString *)text {
    NSString *regEx = @"09\\d{9}";
    NSRange range = [text rangeOfString:regEx options:NSRegularExpressionSearch];
    return range.location != NSNotFound;
}

Answer 2

I would go with

(0|۰)(9|۹)(\d|[dummy]){9} //<-- \d being any digit

Replace dummy with the numbers of the alphabet you want to support

Answer 3

You can try to use this Regex:

09[0-9]{9}

REGEX DEMO

You can try to test it in your function itself like this:

-(BOOL) validateAlphabets: (NSString *)text{      
     NSString *Regex = @"what should be here?!";
     NSPredicate *TestResult = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", Regex];
     if(TestResult evaluateWithObject: text)
     return true;
     else
     return false;
}