So here is my current code for catching an InputMismatchException error
int weapon = 0
boolean selection = true;
while(selection) {
try {
System.
In the first place, you already have a loop with which to prompt for and scan the desired int
. You do not need to duplicate that behavior in your exception handler. What you do need to do, however, is discard the mismatching token from the scanner in order to allow a new one to be scanned.
As a secondary matter, your selection
variable appears to be redundant.
It looks like this might do what you're after:
int weapon = 0
while(weapon < 1 || weapon > 3) {
try {
System.out.println("Pick number 1, 2, or 3.");
weapon = scan.nextInt();
} catch(InputMismatchException e) {
//discard the mismatching token
scan.next();
}
}
Try this:
int weapon = 0;
do{
System.out.println("Pick number 1, 2, or 3.");
if(scan.hasNextInt()){
weapon = scan.nextInt();
break;
}else{
System.out.println("Enter an integer only");
scan.nextLine();
}
}while(true);
This will make sure it is an integer and it will keep asking until it gets it.