I\'m doing an exercise in C but I have a problem when at the and I want to repeat the cicle (do while), infact if I type 1 the programme starts again by the top, but it doesn\'t
Or you can try using the function flushall() just before gets()
Your first and most obvious problem is with the left over newline. When you use scanf()
here:
printf("\nDo you want write another text? (1=yes) -> ");
scanf("%d", &j);
}
and you use the %d
format specificer, the function is looking for a number, when you enter a number really you're entering a number and a newline character
> 1<enter key> // which means on stdin you're getting '1''\n'
scanf()
only picks up the 1 and leaves the newline which your gets()
function then picks up, so it looks like it's skipping the input. All you need to do is consume that newline character, one quick fix would be to consume it with getchar()
:
printf("\nDo you want write another text? (1=yes) -> ");
scanf("%d", &j);
getchar();
}
Now your program works as you'd expect.
Other issues of note:
int
type, even if it's just a return 0
gets()
, even then man page for gets()
says Never use gets(). That's usually a good indication not to. ;) So replace that line with fgets(testo, sizeof(testo), stdin);
printf("\nThe text is composed by % characters\n", cch);
so you're getting garbage output, that should have been %d
It's because the scanf
call at the end of the loop doesn't read the newline. Instead this newline is read by your gets
call.
A simple solution is to add a space to the end of the scanf
format string, like so:
scanf("%d ", &j);
This will make scanf
skip trailing whitespace in the input.
Another solution is to put an extra fgets
after the scanf
, but then don't add the extra space in the format string:
scanf("%d", &j);
fgets(testo, sizeof(testo), stdin);
Or use fgets
to get the line, and then use sscanf
to extract the answer:
fgets(testo, sizeof(testo), stdin);
sscanf(testo, "%d", &j);