List the content of a directory specified by loop indices

Question

I\'m working with numerical weather forecast named as follow:

sub_gfsanl_4_2011MMDD-IIII-FFFF.grb2

-MM stands for month from 01 to 12

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Answer 1

You cannot use ${mi}${di} in shell. They are Fortran variables, not shell variables. You must put the numbers into the string inside Fortran. Use some of the established methods. They were treated here many times in Convert integers to strings to create output filenames at run time and its duplicates (see Related on the right).

Answer 2

Well thanks to Vladimir suggestion here what i did to solve my problem!

program test_ec


implicit none

integer :: mi,di,iiii,fff
 character(len=1024) :: filename
 character(len=1024) :: format_string
 logical exist

mi=1
CALL chdir('/media/Hello/ncfiles/GFS' )

!do di=1,10
     do iiii=0,18,6
         do fff=0,18,6

                   format_string = "(A17,i2.2,i2.2,A1,i4.4,A1,i3.3,A8)"
                    write (filename,format_string) "sub_gfsanl_4_2011",mi,di,"_",iiii,"_",fff,".grb2.nc"

                    inquire(file=trim(filename), exist=exist) 

                           if (exist) then

                                   write(*,*) 'file exists i can do do whatever i want with this file'
                           else
                                   write(*,*) 'I did not find that file.'

                           end if
enddo
   enddo
     enddo

end program test_ec