Build a tree menu with li tag from array

Question

I am retrieving an array and I made function to structure the array so it looks tree array. How to make tree menu with list tag (ul, li)

function buildTree(array         


        

Answer 1

//build Tree structure from array
function buildTree(array &$elements, $parentId = 0, $elkey = null) {
    $branch = array();

    foreach ($elements as $key=>$element) {
        if ($element[$elkey]['parent_id'] == $parentId) {
            $children = buildTree($elements, $element[$elkey]['id'], $elkey);
            if ($children) {
                $element['children'] = $children;
            }
            $branch[$element[$elkey]['id']] = $element;
            unset($elements[$key]);
        }
    }
    return $branch;
}
//Build Menu       
function buildMenu($arr, $elmkey) {
    echo "<ul>";
    foreach ($arr as $val) {
            if (!empty($val['children'])) {
                    echo "<li>" . $val[$elmkey]['title'];
                    menu($val['children'], $elmkey);
                    echo "</li>";
            } else {
                    echo "<li>" . $val[$elmkey]['title'] . "</li>";
            }
    }
    echo "</ul>";
}

$menuTree = buildTree($systemPageCategories, 0, 'SystemPageCategory');
echo menu($menuTree, 'SystemPageCategory'); 

buildMenu() Reference

Answer 2

Try this example, pass $menuTree variable to buildMenu function.

    function buildMenu($menus)
    {
    $data = '';
    foreach ($menus as $key => $menu) {
        if ($key == 'children' && !empty($menu)) {
            $data .= buildMenu($menu);
            continue;
        }

        $data .= '<li><a href="'.$menu['url'].'">'.$menu['title'].'</a></li>';
    }

    if (!empty($data)) {
        $data .= '<ul>'.$data.'</ul>';
    }

    return $data;
   }