Why is first for loop iteration skipped?

Question

my code is yielding an unexpected result. It seems my for loop skips the first iteration and I don\'t understand why.

public static void main(String[] args) {

         


        

Answer 1

    number = get.nextInt();
     // if i enter 4 then it will 4\n and nextInt will take only 4 
     // and the \n will be taken as input by the getline.
    get.nextLine();  
     //this will return the "" from ""\n . so adding this will solve your problem
    family_array = new String[number];

Answer 2

What worked for me was instantiating a new Scanner in each iteration:

for(int i = 0; i < number; i++)
{
    System.out.println("Enter family member name: ");

    Scanner loopGet = new Scanner(System.in);
    family_name = loopGet.nextLine();
    family_array[i] = family_name;
}

Answer 3

Currently your call to Scanner#nextInt is not consuming the newline character so it is being passed through to your first call of Scanner#nextLine, therefore it does not block.

You will need to add

get.nextLine();

after calling nextInt so that your first call to nextLine will block for IO.

Answer 4

Notice that blank line between 4 and 1?

4
       //this is it
1

When you call get.NextInt() you'd not eating the whole line, just the next int. The empty rest of the line is eaten in your first loop iteration. Add a call to get.nextLine() after reading the int.

Answer 5

I am going to say it is because you still have a buffered CR/LF - so the first one is set to blank. Notice the blank line as you print your family names (numbers). That is your blank family name.

The keyboard input is a buffered stream - it has your 5, and it has a CR/LF (or perhaps just a LF, depending on your OS).

You probably want to get the LINE and then do a string.convert, atoi, system.convert (whichever one is for Java) to get the #.