Pandas Delete Part of String

Question

>>> df
                       Time
    5/10/2017 (135) 01:05:03
    5/11/2017 (136) 04:05:06

Given an input date such as this in a DataFrame,

Answer 1

You can use replace by regex:

First need escape () by \ because special chars in regex, then match all ints by \d+ and last match zero or more whitespaces after ) by \s*.

---

df['Time'] = df['Time'].str.replace("\(\d+\)\s*", '')
print (df)
                 Time
0  5/10/2017 01:05:03
1  5/11/2017 04:05:06

And if need convert to datetime:

df['Time'] = pd.to_datetime(df['Time'].str.replace("\(\d+\)\s*", ''))
print (df)
                 Time
0 2017-05-10 01:05:03
1 2017-05-11 04:05:06

EDIT:

In your sample are mising escaping chars \ and is possible use instead \d+ [0-9]+:

df['Time'].replace('\([0-9]+\)\s*','', regex=True, inplace=True)
print (df)
                 Time
0  5/10/2017 01:05:03
1  5/11/2017 04:05:06