I am writing a method which converts Integer data type from a List of lists, to a primitive type \"int\" of \"array of array\".
Question
<This
tempArray[i][j] = ll.get(j);
should be something like
tempArray[i][j] = ll.get(i).get(j);
However, you have a few other bugs (you need to declare the arrays); you can also shorten the initialization routines. Something like,
static int[][] convert(int[] set) {
List<List<Integer>> ll = new ArrayList<>();
ll.add(Arrays.asList(1,2));
ll.add(Arrays.asList(2));
ll.add(Arrays.asList(2,3));
System.out.println(ll + " " + ll.size());
int[][] tempArray = new int[ll.size()][];
for (int i = 0; i < ll.size(); i++) {
tempArray[i] = new int[ll.get(i).size()];
for (int j = 0; j < tempArray[i].length; j++) {
tempArray[i][j] = ll.get(i).get(j);
}
}
return tempArray;
}
To answer your exact question, yes an Integer
can be converted to an int
using the intValue()
method, or you can use auto-boxing to convert to an int
.
So the innermost part of your loop could be either of these:
tempArray[i][j] = ll.get(i).get(j).intValue();
tempArray[i][j] = ll.get(i).get(j);
However, we can also take a different strategy.
As a modification of this answer to a similar question, in Java 8 you can use Streams to map to an integer array. This structure just requires an extra layer of mapping.
List<List<Integer>> list = new ArrayList<>();
int[][] arr = list.stream()
.map(l -> l.stream().mapToInt(Integer::intValue).toArray())
.toArray(int[][]::new);
Ideone Demo
I think you don't need API to convert Integer to int. Just because Integer itself has its own method. Let's see following example
Integer integerObj = new Integer(100);
int intValue = integerObj.intValue(); // intValue = 100