How to sort files by number in filename of a directory? [duplicate]

Answer 1

You can replace the ".txt" and then convert the value to int and sort.

Ex:

for file in sorted(os.listdir(filepath), key=lambda x: int(x.replace(".txt", ""))):
    print(file)

Answer 2

Could use a lambda expression

import os

filelist = os.listdir(path)
filelist = sorted(filelist,key=lambda x: int(os.path.splitext(x)[0]))

for file in filelist:
    print(file)

Outputs as:

1.txt
2.txt
3.txt
4.txt
5.txt
6.txt
7.txt
8.txt
9.txt
10.txt