I have a serious problem, maybe to some it\'s not so serious, but as I am not good with programming, for me it\'s a really tough problem. I will try to explain all clearly:
$result = mysql_query("SELECT * FROM test_image WHERE image = ''") or die(mysql_error());
while($row = mysql_fetch_array($result))
{
echo 'Working with id '.$row['id'].' and name '.$row['name'].'<br />';
// DO YOUR CODE FOR THIS ROW IN YOUR TABLE
}