Conversion from double to integer [duplicate]

Answer 1

Try this and see why!

#include <iostream>
#include <iomanip>
#include <cmath>

using namespace std;

int main(){
    int x = 1000;
    double cube = pow(x, 1.0/3.0);
    int a = cube;
    cout<<"cube="<< fixed << setprecision(16) << cube<<endl;
    cout<<"a="<<a<<endl;
}

Answer 2

Because the cuberoot is very close to 10 but not quite 10. std::cout truncates and rounds the number to 10, but a double to integer conversion will strip the decimal which is why a = 9. To solve this problem, you can use std::round():

int a=round(cuberoot);