Java. HSSF. Apache-poi. How to modificate code

前端 未结 3 1553
無奈伤痛
無奈伤痛 2021-01-26 04:06

My data is stored in a format(look down): [-] means a blank cell, on the right may be only 10 columns, after the space. Something like this:
[string0]

相关标签:
3条回答
  • 2021-01-26 04:47

    External Link: Busy Developers' Guide to HSSF and XSSF Features

    Here is an example that should work.

    Maven Dependencies:

    <dependency>
        <groupId>org.apache.poi</groupId>
        <artifactId>poi</artifactId>
        <version>3.9</version>
    </dependency>
    <dependency>
        <groupId>org.apache.poi</groupId>
        <artifactId>poi-ooxml</artifactId>
        <version>3.9</version>
    </dependency>
    

    Code:

    import org.apache.poi.hssf.usermodel.HSSFDataFormatter;
    import org.apache.poi.openxml4j.exceptions.InvalidFormatException;
    import org.apache.poi.ss.usermodel.*;
    
    import java.io.File;
    import java.io.FileInputStream;
    import java.io.IOException;
    import java.io.InputStream;
    import java.util.Iterator;
    
    public class StackOverflowQuestion18095443 {
    
        public static void main(String[] args) {
            if(args.length != 1) {
                System.out.println("Please specify the file name as a parameter");
                System.exit(-1);
            }
            String sfilename = args[0];
            File file = new File("C:\\Users\\student3\\" + sfilename + ".xls");
            read(file);
        }
    
        public static void read(File file) {
            try (InputStream in = new FileInputStream(file)) {
                HSSFDataFormatter formatter = new HSSFDataFormatter();
                Workbook workbook = WorkbookFactory.create(in);
                Sheet sheet = workbook.getSheetAt(0);
                Iterator<Row> rowIterator = sheet.iterator();
                while (rowIterator.hasNext()) {
                    Row row = rowIterator.next();
                    StringBuilder rowText = new StringBuilder();
                    Iterator<Cell> cellIterator = row.cellIterator();
                    while (cellIterator.hasNext()) {
                        Cell cell = cellIterator.next();
                        String cellAsStringValue = formatter.formatCellValue(cell);
                        rowText.append(cellAsStringValue).append(" ");
                    }
                    System.out.println(rowText.toString().trim());
                }
            } catch (InvalidFormatException | IOException e) {
                e.printStackTrace();
            }
        }
    }
    

    As for terminating the iteration you can conditionally break from the loop. Or, you could also just not use an iterator. Notice that you can obtain a Cell from a Row using a named reference (this allows you to refer to a cell by name, such as "A2", just like you would in Excel) or simply by the column index within the row.

    0 讨论(0)
  • 2021-01-26 04:53

    If I am clear you just want to filter your first column string and rest seperately.

    Why not you just use a simple counter for this:

     while(rowIterator.hasNext()) {
        Row row = rowIterator.next();
        String RowContent = null;
        Iterator<Cell> cellIterator = row.cellIterator();
        while(cellIterator.hasNext()) {
            Cell cell = cellIterator.next();
            RowContent=RowContent+cell.toString();
        }
        //Code for saving RowContent or printing or whatever you want for text in complete row
    }
    

    RowContent will give concatenation of each cells of a single row in each iteration.

    0 讨论(0)
  • 2021-01-26 04:53

    Like you did in the switch block with "break". But what i think you want is this:

    Iterator<Cell> cellIterator = row.cellIterator();
    boolean stop = false;
    while(cellIterator.hasNext()) {
    
      Cell cell = cellIterator.next();
    
      switch(cell.getCellType()) {
        case Cell.CELL_TYPE_STRING:
          System.out.print(cell.getStringCellValue() + "\t\t");
          list1.add(cell.getStringCellValue());
          stop = true;
          break;
      }
    
      if (stop) {
        break;
      }
    }
    

    This would stop the while loop when you found a string cell and will then operate on the next row. Make any possible condition you need to break the while loop. For example collect string columns and when you found the desired set stop to true, to get to the next row.

    0 讨论(0)
提交回复
热议问题