Javascript Function Accepting PHP Variables

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I\'m drawing a complete blank why this isn\'t working. I can do it with one variable passing through, but not two. When I use actually numbers like getnt(1,2) it wo

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3条回答

佛祖请我去吃肉

2021-01-26 03:04

You could always try:

<script type="text/javascript">
    function getnt(nid,pnid) {
        window.location = "nt.php?nid=" + nid + "&pnid=" + pnid;
    }
</script>
<body>  
    <a href="#" onclick="getnt(<?php echo $nid; ?>,<?php echo $pnid; ?>)">VIEW</a>
</body>

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春和景丽

2021-01-26 03:08

Your question is probably best answered by looking at the rendered HTML source.

In any case, here's how I'd do it using graceful degradation

<script type="text/javascript">
function getnt(element) {
    var href = element.href;
    var nid = element.getAttribute("data-nid");
    var pnid = element.getAttribute("data-pnid");
    return true;
}
</script>
<p><a href="nt.php?nid=<?php echo $nid ?>&amp;pnid=<?php echo $pnid ?>"
      data-nid="<?php echo $nid ?>"
      data-pnid="<?php echo $pnid ?>"
      onclick="return getnt(this)">VIEW</a></p>

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-上瘾入骨i

2021-01-26 03:15
If the ID and pnID are strings, enclose them with brackets like this.
```
<body>  
  <?php
    echo "<a href='#' onclick=\"getnt('$nid','$pnid')\">VIEW</a>";
  ?>
  </body>
```
If still not working, You can debug your code
1. View the source code in browser, make sure it generates correctly.
2. Put some alert messages in the javascript function. Install Firebug if you have Firefox or see
3. Javaascript console if you get any javascript errors.
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