check associative array contains value

Question

    Array (    
    [0] => Array ( 
               [questionID] => 47
               [surveyID] => 51
               [userID] => 31 
               [question         


        

Answer 1

foreach($mainarray as $array ){ //check for each 
  if($array['required']==1)
   //doSome Task
  if($array['required']==0)

Answer 2

This is probably the most hackish solution I'll come up with all this morning, but if you are shooting for a quick one-liner, this should do:

if(in_array(1, array_column($myArray, 'required')))
   echo 'required';

Edit: This assumes you've got PHP 5.5+ at hand

Update: After a closer look at the documentation of in_array(), this should be possible:

if(in_array(array('required' => 1), $myArray))
    echo 'required';

Answer 3

if($yourArr[0]['required']==0)  //Just check for first element in your array
  echo "Zero";
else
  echo "One";

Answer 4

As an alternative, my way independent of the array structure (assume $x holds your data structure):

if (preg_match('/"required":[01]/',json_encode($x))) {
    // The array structure contains "required" => 0 or "required" => 1
} else {
    // Negative
}

Answer 5

Let's say your array name is $myarray

So you can do something like this -

foreach($myarray as $arrelement)
{
    if(isset($arrelement[required]) && $arrelement[required] == 1) //choose 1 or 0 in code as per your need
    {
         //traverse your array and do needful
    }
}