String variable may not have been initialized (error diects to line 34)

Question

I\'ve been trying to get the string initialize, but to no avail. I have tried all of the solutions I have come across and I am not sure whether it is because of my ineptness or

Answer 1

You can initialize the values of Strings in two ways:

String abc = "I love basketball";

or

String abc = new String("I love basketball");  

What you are seeing is a warning and not an error. If you insist on not putting a value into the String, just do

String abc = null;    

or

String abc = ""  

In the latter case, your String is initialized to the characters between the quotations. Nothing, basically, but it is not null.

To avoid potential NPE problems, compare the Strings as follows:

"rock".equalsIgnoreCase(playerChoice);

Answer 2

String computer; // not initialized

change this to

String computer = null;  or ""// initialized
if (player.compareTo(computer) == 0)

because, the variable computer will assigned based on the condition. If the above condition you mentioned is not satisfied. The value is none, so only it show the error.

Answer 3

The compilator see you have String computer. He can also see that this computer is initialized for answer 1 or 2 or 3. But because it cant read logic, it does not know anything about if answer can be or cannot be lower or higher so it is assuming the worst possibility - that computer will not be initialized.

Just change your up line to

String computer = "";

and it should be fine.

Answer 4

If I understand your question at all, than keep in mind you can't do this in Java:

String str = "here is some
    random text";

What you can do is

String str = "here is some " + 
    "random text";

In other words - can't break a string at the end of the line, gotta close it and use a + sign.