Password Authentication c++

Question

Hi this is my first time using classes so apologies for my poor explanation. Basically I am making a password function for an elevator program. LogIn is the name of my class, wh

Answer 1

Try this, sweet and simple:

cout << "nameAttempt: " << endl;
cin >> nameAttempt; 

LogIn Authenticate(name, nameAttempt);
attempts = 0;
while (attempts<2)
{
    if (Authenticate.getName() == Authenticate.getNameAttempt()) 
    {
      return true;
     }

     cout<<"Incorrect name. Try again"<< endl;
     cout<< "" << endl;

     cout << "Enter Name:"<< endl;
     cin >>nameAttempt;
     attempts++;
     LogIn Authenticate(name, nameAttempt);
 }
return false;

Answer 2

You initialize local function variable

int attempts = 0; 

so exit condition in while loop will be trigerred third times the code

 if (attempts++ ==2)

is run, so you will print two times:

while (Authenticate.getName() != Authenticate.getNameAttempt())
{
    if (attempts++ ==2) // increment attempts
{
    return false;
}      

It looks as it was done deliberately to exit after second print, so your confusion is hard to understand. Use the debugger, this kind of error is very easy to investigate.

Answer 3

In the retry loop, you still need to validate the attempted name and break the loop if the name is accepted.

Answer 4

I think the code should be like this:

while (1)
    {
        if (Authenticate.getName() == Authenticate.getNameAttempt())
        {
            return true;
        }
        else        
        {
            if (attempts++ == 2)
            {
                return false;
            }
            cout << "Incorrect name. Try again" << endl;
            cout << "" << endl;

            cout << "Enter Name:" << endl;
            cin >> nameAttempt;

            Authenticate.setNameAttempt(nameAttempt);
        }
    }