Why is parseInt() not working? [duplicate]

Answer 1

value1 = "10";
value2 = "5";

var calculatedAnswer = parseInt(value1) + parseInt(value2);
alert(calculatedAnswer)

You need to use parseInt output

Answer 2

Because you are not assigning parsed value to value1 and value2, so parseInt(value1) wont change. You can use the below way or change parseInt(value1) to value1 = parseInt(value1) same to value 2 also;

You can also change string to number by adding + in the front of string

value1 = "10";
value2 = "5";

var calculatedAnswer = parseInt(value1) + parseInt(value2);
console.log(calculatedAnswer)

console.log((+value1) + (+value2))

Answer 3

You can assign the parsed values back to the variables:

var value1 = "10";
var value2 = "5";

value1 = parseInt(value1);
value2 = parseInt(value2);

var calculatedAnswer = value1 + value2;

Answer 4

You have to store the parseInt value somewhere and use it. Like

value1 = "10";
value2 = "5";

var parsed1 = parseInt(value1);
var parsed2 = parseInt(value2);

var calculatedAnswer = parsed1 + parsed2;