Extracting specific files within directory - Windows

Question

I am running a loop which needs to access circa 200 files in the directory.

In the folder - the format of the files range as follows:

1. Excel_YYYYMMDD.txt<

Answer 1

Here is a cheap way to do it (and by cheap I mean probably not the best/cleanest method):

import glob
l = glob.glob("Excel_[0-9]*.txt")

This will get you:

>>> print(l)
['Excel_19900717_orig.txt', 'Excel_19900717_V2.txt', 'Excel_19900717.txt']

Now filter it yourself:

nl = [x for x in l if "_orig" not in x and "_V2" not in x]

This will give you:

>>> print(nl)
['Excel_19900717.txt']

The reason for manually filtering through our glob is because the glob library does not support regex.

Answer 2

Use ^Excel_[0-9]{8}\.txt as the file matching regex.