Selenium click next button yields selenium.common.exceptions.ElementClickInterceptedException [duplicate]

Answer 1

Here is a very simple running code snippet that uses XPATH to find the button Text "Se flere".

from selenium import webdriver

driver = webdriver.Firefox()
driver.get("https://coop.no/sortiment/obs-bygg/hageuterom/hytter-boder-og- 
drivhus")
element = driver.find_element_by_xpath('//button[text()="Se flere"]')
element.click()

Answer 2

To click on Se flere you have to induce WebDriverWait for the element_to_be_clickable() and you can use either of the following Locator Strategies:

• Using CSS_SELECTOR:

  driver.get('https://coop.no/sortiment/obs-bygg/hageuterom/hytter-boder-og-drivhus')
  WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "button[type='CategoryPage']"))).click()
  

• Using XPATH:

  driver.get('https://coop.no/sortiment/obs-bygg/hageuterom/hytter-boder-og-drivhus')
  WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//button[@type='CategoryPage']"))).click()
  

• Note : You have to add the following imports :

  from selenium.webdriver.support.ui import WebDriverWait
  from selenium.webdriver.common.by import By
  from selenium.webdriver.support import expected_conditions as EC
  

• Browser Snapshot:

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Reference

You can find a couple of detailed discussion in:

• Can not click on a Element: ElementClickInterceptedException in Splinter / Selenium
• ElementClickInterceptedException: Message: element click intercepted: Element is not clickable with Selenium and Python