How can I make the days of the month be printed according to each day (ex: Su Mo Tu We…etc)?

Question

I have a big String with numbers 1-31. and how would i be able to center the name of the month?

My code:

class Month

  attr_reader :month, :year

  def          


        

Answer 1

The String class in Ruby has a center method:

weekdays = "Su Mo Tu We Th Fr Sa"
month    = "#{month_names} #{year}"

output   = [
  month.center(weekdays.size), 
  weekdays
].join("\n")

puts output
#      April 2015     
# Su Mo Tu We Th Fr Sa

---

The following does not really answer your question. It is just a complete rewrite of your code, because I was bored:

require 'date'

class Month
  attr_reader :month, :year

  def initialize(month, year)
    @month = month
    @year  = year
  end

  def first_of_month
    Date.new(year, month, 1)
  end

  def last_of_month
    Date.new(year, month, -1)
  end

  def month_name
    last_of_month.strftime('%B')
  end

  def days_in_month
    last_of_month.day
  end

  def to_s
    [].tap do |out|
      out << header
      out << weekdays

      grouped_days.each do |days|
        out << days.map { |day| day.to_s.rjust(2) }.join(' ')
      end
    end.join("\n")
  end

private
  def header
    "#{month_name} #{year}".center(weekdays.size)
  end

  def weekdays
    'Su Mo Tu We Th Fr Sa'
  end

  def grouped_days
    days = (1..days_in_month).to_a
    first_of_month.wday.times { days.unshift(nil) }
    days.each_slice(7)
  end
end

Month.new(4, 2015).to_s
#      April 2015     
# Su Mo Tu We Th Fr Sa
#           1  2  3  4
#  5  6  7  8  9 10 11
# 12 13 14 15 16 17 18
# 19 20 21 22 23 24 25
# 26 27 28 29 30