Find the median of an array

Question

I wrote some code that returns the median of an unsorted odd numbered array, but it does not return the median of an even numbered array.

I know that in order to find

Answer 1

Here is the answer:

def get_median(sub_a)
    result = -1
    size = sub_a.size
    if size == 0
        result = 0
    elsif size == 1
        result = sub_a[0]
    elsif size == 2
        result = get_average(sub_a[0], sub_a[1])
    else
        sorted_a = sub_a.sort
        index = size / 2
        if size % 2 == 0
            result = get_average(sorted_a[index - 1], sorted_a[index]);
        else 
            result = sorted_a[index];
        end
    end

    '%0.01f' % result
end

Answer 2

I'm going to just jump in with a solution here...

def median(ary)
  mid = ary.length / 2
  sorted = ary.sort
  ary.length.odd? ? sorted[mid] : 0.5 * (sorted[mid] + sorted[mid - 1])
end

Edit - I've incorporated .odd? as per BroiSatse's suggestion.

Answer 3

def get_median(values)
  quotient, remainder = values.sort!.length.divmod(2)
  medians = [values[quotient], values[quotient-(remainder+1) % 2]].uniq
  medians.length > 1 ? medians.map(&:to_f).reduce(:+) / 2 : medians[0]
end

This should work, but let me know if it does not.

edit forgot to add .to_f to medians values. Here is my testing in Pry.

[1] pry(main)> def get_median(values)
[1] pry(main)*   quotient, remainder = values.sort!.length.divmod(2)
[1] pry(main)*   medians = [values[quotient], values[quotient-(remainder+1) % 2]].uniq
[1] pry(main)*   medians.length > 1 ? medians.map { |v| v.to_f }.reduce(:+) / 2 : medians[0]
[1] pry(main)* end
=> nil
[2] pry(main)> values = [1,2,3]
=> [1, 2, 3]
[3] pry(main)> get_median values
=> 2
[4] pry(main)> values << 4
=> [1, 2, 3, 4]
[5] pry(main)> get_median values
=> 2.5
[6] pry(main)> get_median values << -1
=> 2
[7] pry(main)> values
=> [-1, 1, 2, 3, 4]
[8] pry(main)> values << 11
=> [-1, 1, 2, 3, 4, 11]
[9] pry(main)> get_median values << -1
=> 2
[10] pry(main)> values
=> [-1, -1, 1, 2, 3, 4, 11]
[11] pry(main)> values.delete_if { |v| v == -1}
=> [1, 2, 3, 4, 11]
[12] pry(main)> values << -1
=> [1, 2, 3, 4, 11, -1]
[13] pry(main)> get_median values
=> 2.5
[14] pry(main)>

Answer 4

  a = [1,2,4,5,3,6]
  sorted = a.sort
  list = sorted.length
  if list %2 != 0
    puts sorted[list/2]
  else
    puts (sorted[list/2]+sorted[(list/2)-1])/2.0
  end