Making a loop to form a list?

Question

def make_services(routes_data):
    routes = []
    curr_route = []
    x = split_routes(routes_data)
    service_data1 = x[1]  # (’106’, [(’106’, ’1’, ’1’, ’43009’), ..         


        

Answer 1

you return only [(tuple([service_code] + [l] + [[curr_route]]))] which is only one entry, this is why you get only:

[('106', ['1', '2'], [['43009', ... '43009']])]

you need to store all entries in one list, say, results and append to it each entry in your loop, something like:

results.append(tuple([service_code] + [l] + [[curr_route]]))

and return:

return results 

Answer 2

I think you need something more like:

def make_services(routes_data):
    output = []
    for service in split_routes(route_data):
        # service == (’171’, [(’171’, ’1’, ’1’, ’59009’), ... , (’171’, ’2’, ’73’, ’59009’)])
        code = service[0] # 171
        directions = []
        route = []
        for stop in service[1]:
            # stop == (’171’, ’1’, ’1’, ’59009’)
           if stop[1] not in directions:
               directions.append(stop[1])
           route.append(stop[3])
        output.append((code, directions, route))
    return output

Each item in output will be a three-tuple of the code, the directions list and the route list, e.g.

output == [('171', ['1', '2'], ['59009', ..., '59009']), ... ]

You could consider making (some of) these values int() for further processing, or you can leave them as strings.