comparing two variables returns false result

Question

Why does this always return true:

$s = \'334rr\';
$i = (int)$s;

if ($i == $s) {
    echo true;
} else {
    echo false;
}

If I ec

Answer 1

From the manual:

If you compare a number with a string or the comparison involves numerical strings, then each string is converted to a number and the comparison performed numerically.

So: ($i == $s) is the same as ($i == (int)$s) for the values you've given.

Use === to avoid type-juggling.

Answer 2

Comparing strings to an int is not recommended. You should use the === instead which will verify the same data type as well as the same value.

Answer 3

PHP converts the $s string to an integer when comparing to another integer ($i). It basically does this (well, i don't know what it does internally, but it boils down to this):

if($i == (int) $s)

Which makes the statement true

Answer 4

When compare string with integer using ==, string will try to case into integer.

Answer 5

Try this

$s = '334rr';
$i = intval($s);
if ($i == $s) {
 echo true;
 } else {
  echo false;
}