JqGrid - Merging the Grid Column Model javascript & JSON response

Question

Is it possible to merge the Column Model javascript file and the raw data JSON response into 1 file?

Oleg - here you go:

JSON - codes.js

Answer 1

You should modify the code of buildSelect to about the following

buildSelect: function (data) {
    var s = '<select>', codes, i, l, code, prop;
    if (data && data.codes) {
        codes = data.codes;
        for (i = 0, l = codes.length; i < l; i++) {
            code = codes[i];
            // enumerate properties of code object
            for (prop in code) {
                if (code.hasOwnProperty(prop)) {
                    s += '<option value="' + prop + '">' + code[prop] + '</option>';
                    break; // we need only the first property
                }
            }
        }
    }
    return s + "</select>";
}

Additionally you should use ajaxSelectOptions to set any options of the corresponding $.ajax request which you jqGrid if it get data from from the server. In any way you should use relative URLs like json/codes.json or /json/codes.json instead of http://localhost/json/codes.json.

An example of ajaxSelectOptions parameter could be the following

ajaxSelectOptions: {
    dataType: 'json',
    cache: false
}

If contentType: "application/x-javascript; charset=utf-8" is really required you can add it as additional property of ajaxSelectOptions.

How you can see from the demo the selects will be produced correct from your JSON data by above buildSelect function. The select looks like

<select role="select" id="2_code" name="code">
    <option value="code1" role="option">WFH - Work From Home</option>
    <option value="code2" role="option">OST - Onsite</option>
</select>