I have been trying to use the c++ 11 mersenne_twister_engine class( http://www.cplusplus.com/reference/random/mersenne_twister_engine/) to generate numbers in the interval [0,1]
In C++, /
on integer numbers results in an integer number. For example 11 / 2 results in 5, not 5.5. In the same way a / b
is always zero if a < b
.
Your problem is here:
generator()/generator.max()
generator()
and generator.max()
both return integers and of course, generator.max() >= generator()
, so the result is zero (unless you are very lucky to get the max
number in which case the result would be one).
To fix this, you can simply cast it:
(double)generator()/generator.max()
Perhaps you are looking for generate_canonical<double, bits>(gen)? This will generate a decimal value uniformly distributed in the interval [0,1)
with bits
bits of randomness (53 being the standard maximum available for a double).
Using one of the distributions provided in the random header probably makes more sense. As Cubbi points out std::bernoulli_distribution looks like it fits your problem well. It will generate true
or false
according to the distribution parameter you pass in:
#include <iostream>
#include <random>
#include <vector>
#include <algorithm>
const int WIDTH = 5 ;
const int HEIGHT = 5 ;
const double VERT_CONNECTIVITY = 0.25 ;
int main()
{
std::random_device rd;
std::mt19937 gen(rd());
// give "true" 1/4 of the time
// give "false" 3/4 of the time
std::bernoulli_distribution d(VERT_CONNECTIVITY);
std::vector<int> vert_con( WIDTH * HEIGHT ) ;
std::generate( std::begin(vert_con), std::end( vert_con ), [&] () { return d(gen) ; } ) ;
for (int i=0; i < WIDTH * HEIGHT; i++)
{
std::cout << vert_con[i] << " " ;
}
std::cout << std::endl ;
return 0 ;
}
The mersenne_twister_engine
returns results of type UIntType
. If you want the result to be a double, you need to cast it to a double.
double random = (double)generator()/generator.max();