Calculate the highest duplicate integers of two associative arrays

Question

Given 2 associative arrays:

$fruits  = array ( \"d\" => \"lemon\", \"a\" => \"orange\", \"b\" => \"banana\", \"c\" => \"apple\" );
$fruits2 = array          


        

Answer 1

You're probably chasing the wrong solution. To find the highest duplicate in an array I'd use this (PHP 5.3+ syntax):

max(array_keys(array_filter(array_count_values($array), function ($i) { return $i >= 2; })))

Do this for both arrays and compare which result is higher. Trying to compare both against each other at the same time is too convoluted.

Answer 2

Got it working this way :

$n = count($fruits);
for ( $i = 0; $i < $n; $i++)
{
  $cur_vals_1 = each ($fruits);
  $cur_vals_2 = each ($fruits2);

  $sum1 += $cur_vals_1['key'] * $cur_vals_1['value'];

  ...
}

Answer 3

Use array array_values ( array $input ) function and compare them.

 $value1=array_values($fruits);
 $value2=array_values($fruits2);

 for ( $i = 0; $i < count($value1); $i++)
 {
   $test[] = $value1[$i] == $value2[$i] ? TRUE : FLASE;
 }

Answer 4

You don't need the ternary operator.
Also, be careful with count() as it will fail if your array is null.
They also need to be equal lengths or you'll get an error.

if( is_array($value1)  && is_array($value2) && count($value1)==count($value2) ) {
    for ( $i = 0; $i < count($value1); $i++)
    {
        $test[] = ($value1[$i] == $value2[$i]);
    }
}