converting an array of integers to string

Question

If I have an array that looks like

int digits[size] = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 2, 3, 0, 4}

I want to remove the leading zeros and to d

Answer 1

you can use C++11 function std::to_string() here is an example

#include <string>
#include <iostream>

int main()
{
   int size = 15;
   int digits[size] = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 2, 3, 0, 4};
   std::string result = "";

   for (int i = 0; i < size; i++)
   {
      if (!(digits[i] == 0 && result.size() == 0))
         result += std::to_string(digits[i]);
   }

   std::cout << result << std::endl;
}

you can check if a string is numeric using this function

bool isNb(std::string str)
{
  if (str.size() == 0)
    return false;

  for (int i = 0; i < str.size(); i++)
  {
    if (std::isdigit(str.at(i)) == false)
      return false;
  }

  return true;
}

Answer 2

To answer your actual question (How to remove the leading zeros?) here a solution without strings:

#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;

int main() {
    std::vector<int> x = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 2, 3, 0, 4};
    // ...or if you insist on the array...
    // int x[] = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 2, 3, 0, 4};
    // std::vector<int> x = {x,x+15};
    auto it = std::find_if_not(x.begin(),x.end(),[](int i){return i==0;});
    std::vector<int> y{it,x.end()};
    for (auto i : y) std::cout << i << " ";
}

prints:

1 2 3 0 4

Answer 3

You can use a string stream to convert from any type to string:

#include <sstream> //<-- ALLOWS USE OF std::stringstream 
const int size = 15;

int digits[size] = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 2, 3, 0, 4};

std::stringstream ss;  //<-- DECLARE STREAM

int k;
for (k = 0; k < size; ++k)
        if (digits[k] != 0)
                break; //FIND FIRST NON-0 INDEX

for (int i = k; i < size; ++i)
                ss << digits[i]; //ADD TO THE STREAM s

std::cout<< ss.str() << std::endl; //PRINT STREAM

12304

Answer 4

Try the following way:

int i = 0;
while(digits[i] == 0) i++;
for (; i < size; i++)
   result += to_string(digits[i]);

Answer 5

Instead of changing digits with your for loop, add them with

 number += to_string(digits[i]);

Also, you can remove the toString line you have, and just use it as I put here.

As to your other question, just use a for loop to check each digit in the string and its ASCII value, if there is any whose ASCII value is less than 48 or greater than 57 then it's not a number.