I\'m struggling with a backtracking algorithm to determine wether a Sudoku has a unique solution or if it has multiple Solutions. Here\'s the backtracking code i use:
The reset must be inside the for loop and after the if solve
condition
for (int val = 1; val <= 9; ++val) {
if (legal(i,j,val,cells)) {
cells[i][j] = val;
if (solve(i+1,j,cells))
return true;
cells[i][j] = 0; // reset on backtrack
}
}
If you return a number instead of a boolean, you can distinguish between cases where there are 0, 1, or more than 1 solution(s).
// returns 0, 1 or more than 1 depending on whether 0, 1 or more than 1 solutions are found
static byte solve(int i, int j, int[][] cells, byte count /*initailly called with 0*/) {
if (i == 9) {
i = 0;
if (++j == 9)
return 1+count;
}
if (cells[i][j] != 0) // skip filled cells
return solve(i+1,j,cells, count);
// search for 2 solutions instead of 1
// break, if 2 solutions are found
for (int val = 1; val <= 9 && count < 2; ++val) {
if (legal(i,j,val,cells)) {
cells[i][j] = val;
// add additional solutions
count = solve(i+1,j,cells, count));
}
}
cells[i][j] = 0; // reset on backtrack
return count;
}