Dynamic key names [duplicate]

Answer 1

Although the language won't accept arithmetic names unless you are actually making a string out of it, I think you will have better semantic by using arrays instead of many simlar-named variables.

For example, if there is many indexed obj.warehouse, you should initialize it as an array:

obj.warehouse=[];

Then, to put something into it:

obj.warehouse[x] = inventory.inventory_obj[x].warehouse;

It will be easier for you to access it later because you won't have to concatenate every time you want to access a warehouse. Also, as long as there are "concatenating" accesses, debugging can be a pain whenever something is renamed.

Answer 2

Your can't have + in the name obj.warehouse_+x and all other instances like that.

You need to use: obj["warehouse_" + x] for dynamic object key names.

For concatenation try using:

obj["warehouse_" + x] = obj["warehouse_" + x]  + inventory.inventory_obj[x].warehouse;

There is no concatenation operator for objects like there is for strings or numbers (+=).

Answer 3

To create the property name dynamically, use the square bracket notation:

obj['warehouse_' + x] = nventory.inventory_obj[x].warehouse;