Better way to declare uninitialized variables

Question

Some libc functions, e.g. sigemptyset(set: *mut sigset_t) take a pointer to a variable, treat it as uninitialized and initialize it.

I end up with this code:

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Answer 1

Luckily, tuples are normal types, too. So how about:

let (mut newmask, mut oldmask, mut pendmask) = std::mem::uninitialized();

However, it won't get much nicer than this. Your best bet is to combine all your variables into a bigger type (like a tuple or a struct) and un-initialize that.

But it's fine that unsafe things are verbose and annoying to write. Uninitialized variables are really quite dangerous, especially when dealing with Drop types. I am sure you are already aware, but I still want to make sure everyone reads the documentation of uninitialized() to understand all possible pitfalls.