TABLE price
user_id b01 b02 b03 b04 b05 b06 b07 b08 b09
MP01 21 32 12 34 56 26 21 21 26
MO11
Base on your example i think you mean the result is 12. If that is the case you can do
SELECT LEAST(b01, b02, b03, b04, b05, b06, b07, b08, b09) FROM price WHERE user_id = 'MP01'
This is an alternative approach to LEAST. Not easy as Using Least function. But might come in handy in some situations
SELECT MIN(b01) FROM(
select user_id , b01 from price
union all
select user_id , b02 from price
union all
select user_id , b03 from price
union all
select user_id , b04 from price
union all
select user_id , b05 from price
union all
select user_id , b06 from price
union all
select user_id , b07 from price
union all
select user_id , b08 from price
union all
select user_id , b09 from price
) temp
WHERE user_id = 'MP01'
you can use least
select least(b01,b02,b03,b04,b05,b06,b07,b08,b09)
FROM Table1
where user_id='MP01'
you can use the LEAST function, as in:
select least(b01,b02,b03,b04,b05,b06,b07,b08,b09) from price where user_id = 'MP01'
http://dev.mysql.com/doc/refman/5.0/en/comparison-operators.html#function_least