Remove empty spaces and period

Question

I cannot get this regex to work:

\"4.  182 ex\" (number, period, 2 blank spaces, 3 numbers, blank space, 2 characters\"

The regex syntax should

Answer 1

For it to match exactly what you said, use:

(\d)\.\s\s(\d{3})\s\w\w

You'll get it in two groups, first digit and second digit group.

RegEx101 exmple

Regards.

Answer 2

Just remove all characters that are not digit:

Perl:

$string =~  s/\D+//g;

or php:

$string = preg_replace('/\D+/', '', $string);

According to your updated question, you could do:

$string =~ s/^Magic(\d+)\.  (\d{3})\b.*$/$1$2/

or, with php:

$string = preg_replace('/^Magic(\d+)\.  (\d{3})\b.*$/', '$1$2', $string);

Answer 3

^([\d]+)\.[\s]+([\d]+)[\s]..

Tested with perl:

> echo "4. 182 ex" | perl -lne 'print $1,$2 if(/^([\d]+)\.[\s]+([\d]+)[\s]../)'
4182