Or operand with int in if statement

Question

My problem is that program is not reading codes as i intended \"he\" would.

I have

if (hero.getPos() == (6 | 11 | 16)) {
    move = new Object[] {\"Up\",         


        

Answer 1

You could put all the numbers in a collection, and then use the contains() method. Other than that, I don't believe there is any special syntax for comparing like you want to do.

Answer 2

There is no such operator. But if you are comparing number, you can use switch do simulate that. Here is how:

int aNumber = ci.getNumber();
swithc(aNumber) {
    case 6252001:
    case 5855797:
    case 6251999: {
        ...
        break;
    }
    default: {
        ... // Do else.
    }
}

Hope this helps.

Answer 3

boolean theyAretheSame = num1 == num2 ? (num1 == num3 ? true:false):false;

I must admit I haven't checked this but the logic looks correct.

Answer 4

using the answer from:

How can I test if an array contains a certain value?

you could create an array of numbers and check if your ci.getNumber() is in it.

Answer 5

Use:

if (hero.getPos() == 6 || hero.getPos() == 11 || hero.getPos() == 16)) {

This will do what you want.

What you did is comparing hero.getPos() with the result of (6|11|16) which will do bitwise or between those numbers.

Answer 6

The other answers are correct, just thinking differently you may use Sets.

static final Set<Integer> positions = new HashSet<Integer>();
static{
    positions.add(6);
    positions.add(11);
    positions.add(16);
}

if (positions.contains(hero.getPos())){
    move = new Object[] {"Up", "Right", "Left"};
} else {
    move = new Object[] {"Up", "Down", "Right", "Left"};
}