Split strings keeping all trailing empty elements

Question

I am relatively new to java programming. How would you split following lines of Strings separated by semicolons?

String; String; String; String, String; String;;         


        

Answer 1

The issue is the String.Split does not keep the trailing empty elements:

Trailing empty strings are therefore not included in the resulting array.

To include them, use -1 as the second argument (see demo):

String s  = "String; String; String; String, String; String;;String;";
System.out.println(Arrays.toString(s.split(";", -1)));

See this Java reference:

public String[] split(String regex, int limit)
The limit parameter controls the number of times the pattern is applied and therefore affects the length of the resulting array... If n is non-positive then the pattern will be applied as many times as possible and the array can have any length. If n is zero then the pattern will be applied as many times as possible, the array can have any length, and trailing empty strings will be discarded.

Answer 2

Since you stated that you want to contain the spaces, only split on the ; and want to keep 8 arguments for your constructor, we are going to use the split with a limit method.

String.split(String,int)

Example:

String in = "String; String; String; String, String; String;;String;";
String[] s1 = in.split(";");

Gives:

["String"," String"," String, String"," String"," String","","String"]

What is only 7 in length and will fail your constructor.

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String[] s = in.split(";",8);

Gives:

["String"," String"," String"," String, String"," String","","String",""]`

What is 8 in length and will work.

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You can then address your constructor using:

YourObject obj = new YourObject(s[0],s[1],s[2],s[3],s[4],s[5],s[6],s[7]);

Answer 3

Your answer is in the javadoc.

String toto = "A;B;C;D";

String[] tokens = toto.split(";");