Excel VBA: Regular Expression - get file name

Question

How do I get just filename (without path and extension)
like \"MyFileName\"
from the following full path?
C:\\A_B\\C.D\\E_\\F0123456789\\G\\MyFileName.txt

Answer 1

Set regEx = New RegExp
regEx.Pattern = ".*\\"
regEx.IgnoreCase = True
filename = regEx.Replace(fullpath, "")

Answer 2

If it's a real file that you have access to, you can use Dir

sFileOnly = Dir(sPathAndFile)

If it's not a real file or you don't have access to it, this will return an empty string.

Answer 3

InStrRev will find the last occurrence of a character in a string. Search for \ and split it there

FullFileName="C:\A_B\C.D\E_\F0123456789\G\MyFileName.txt"
FileName=mid(FullFileName,instrrev(FullFileName,"\")+1)

now to take off the extension

FileNameWithoutExt=left(FileName,instrrev(FileName,".")-1)

Answer 4

Public Function GetFileNameWithoutExt(ByVal fullPath As String) As String
Dim fileName As String
Dim fileNameWithoutExt As String

Dim lastSlash As Integer
Dim positionOfDot As Integer

lastSlash = InStrRev(fullPath, "\")
fileName = Mid(fullPath, lastSlash + 1)

positionOfDot = InStr(1, fileName, ".")
fileNameWithoutExt = Mid(fileName, 1, positionOfDot - 1)

GetFileNameWithoutExt = fileNameWithoutExt
End Function

Using the immediate window

?GetFileNameWithoutExt("C:\A_B\C.D\E_\F0123456789\G\MyFileName.txt")

EDIT: Another method

Public Function GetFileNameWithoutExt2(ByVal fullPath As String) As String
Dim fileName As String
Dim splittedData
Dim fileNameWithoutExt As String

splittedData = Split(fullPath, "\")
fileName = splittedData(UBound(splittedData))

fileNameWithoutExt = Split(fileName, ".")(0)

GetFileNameWithoutExt2 = fileNameWithoutExt
End Function

Answer 5

    Sub Test()
        Dim fileNameOnly As String
        fileNameOnly = Left$(Split("C:\A_B\C.D\E_\F0123456789\G\MyFileName.txt", "\")(UBound(Split("C:\A_B\C.D\E_\F0123456789\G\MyFileName.txt", "\"))), InStrRev(Split("C:\A_B\C.D\E_\F0123456789\G\MyFileName.txt", "\")(UBound(Split("C:\A_B\C.D\E_\F0123456789\G\MyFileName.txt", "\"))), ".") - 1)
        Debug.Print Strtf    
    End Sub