Regular Expression to find string in Expect buffer

Question

I\'m trying to find a regex that works to match a string of escape characters (an Expect response, see this question) and a six digit number (with alpha-numeric first character)

Answer 1

I found out a few things with some more digging. First of all I wasn't looking at the output of the program but the input of the user. I needed to add the "-o" flag to look at the program output. I also shortened the regex to just the necessary part.

The regex example from @rikh led me to look at why his or my own regex was failing, and that was due to the fact that I wasn't looking at the output but the input. So the original regex that I tried wasn't at fault but the data being looked at (missing the "-o" flag)

Here's the complete answer to my problem.

interact {
#...
    -o -nobuffer -re {(\[1;14H[a-zA-Z0-9]{1})[0-9]{5}} {
            #get number in place
            set numraw $interact_out(0,string)
            #get just number out
            set num [string range $numraw 6 11] 
            #switch to lowercase
            set num [string tolower $num]
            send_user "  stored number: $num"
    }   
}

I'm a noob with Expect and Tcl so if any of this doesn't make sense or if you have any more insights into the interact flags, please set me straight.

Answer 2

If you just want the number at the end, then this should be enough...

[0-9]{6}

Update with new information

Assuming \n is a newline character, rather than a literal \ followed by a literal n, you can do this...

\r\n\u001B\[1;14H(X[0-9]{5})