Readin a .txt file and put the elements in a list (Python)

Question

Im new in Python and i need some help. i got a .txt file in this form:

Time[tab]Signal

0[tab]1.05

0.5[tab]1.06

1[tab]1.09

1.5[tab]1.12

Now

Answer 1

Change the File_Name= according to your needs.

File_Name = 'aa.txt'
time_list = []
signal_list = []
with open(File_Name,'r') as fh:
    for line in fh:
        line = line.strip() 
        time,signal = line.split()
        time = time.strip()
        signal = signal.strip()
        time_list.append(time)
        signal_list.append(signal)

print(time_list)
print(signal_list) 

Answer 2

I have created a .txt file with same contents that you provided and the program you wrote prints this (multi-dimensional list):

[['Time', 'Signal'], ['0.5', '1.06'], ['1', '1.09'], ['1.5', '1.12']]

By the looks of it your file isn't actually .txt.

To answer your question:

del list1[1]

This will delete the wrong position. To delete Time/Signal line, you should do this instead:

del list1[0]

This is because items in Python lists start at positon 0.

Try this code (list comprehension):

daten = open("extedit.txt", "r")
lines = daten.readlines()
list1 = []
for i in lines:
    list1.append(i.strip().split('\t'));
daten.close()

del list1[0]

zeit = [i[0] for i in list1]

signal = [i[1] for i in list1]

print(zeit)
print(signal)

Answer 3

don't use semicolons in python! As suspected, you are trying to read a RTF file.
First reformat your file. I propose also an other way:

import csv

list1 = []
with open("extedit.txt") as tsv:
    for line in csv.reader(tsv, dialect="excel-tab"):
        list1.append(line[0])

del list1[0]
print(list1)