I have 3 columns.
-----A-----B-----C-----
---Name----ID---Report
In column A I have Names(Can Repeat)
In column B I have IDs (can repeat wi
This seems to be very close to what you are trying to do
=SUMPRODUCT((A2:A1000="John")*(C2:C1000="No")*(IF(FREQUENCY(B2:B1000,B2:B999)>0,TRUE)))
There is one flaw with the frequency in that it ignores the last row.
If I change the frequency formula to FREQUENCY(B2:B1000,B2:B1000)
it will error out as it returns 10 results instead of the desired 9.
EDIT
It is probably better to extend the other ranges than shorten the bins array.
=SUMPRODUCT((A2:A1001="John")*(C2:C1001="No")*(IF(FREQUENCY(B2:B1001,B2:B1000)>0,TRUE)))
You can use a single formula like this:
=SUM(IF(FREQUENCY(IF(A2:A200="John",IF(C2:C200="No",B2:B200)),B2:B200),1))
That's an "array formula that needs to be confirmed with CTRL+SHIFT+ENTER
That gives 3 for your example - note that it requires column B data to be numeric which seems to be the case here.....
My thought is to add column D
with the formula =COUNTIFS(A:A,"="&A2,B:B,"="&B2,C:C,"="&C2)
. This will give you the number of duplicates for each line. If a line returns a 3, then it means there are two other instances of that exact configuration.
Next, create a new table, for testing I did this in columns G
and H
. Column G
is just numbered 1,2,3 etc. beginning in G2
. The Name is a header and reference in cell H1
, in this case John. Then put this formula in cell H2
: =COUNTIFS(A:A,"="&$H$1,C:C,"=No",D:D,"="&G2)/G2
and drag it down. It is essentially counting the instances of each "1" duplicate, "2" duplicate, and "3" duplicate (which might actually be useful). Then just sum the H
column and you should have your answer.