How to use .substring method to start at an index and grab x number or characters after it?

Question

so I\'m parsing html and I\'m trying to create a substring starting at a certain location and stop 941 characters after that. The way the .substring method in Java works is you

Answer 1

Please refer to the String.substring source.

public String substring(int beginIndex, int endIndex) {
    if (beginIndex < 0) {
        throw new StringIndexOutOfBoundsException(beginIndex);
    }
    if (endIndex > value.length) {
        throw new StringIndexOutOfBoundsException(endIndex);
    }
    int subLen = endIndex - beginIndex;
    if (subLen < 0) {
        throw new StringIndexOutOfBoundsException(subLen);
    }
    return ((beginIndex == 0) && (endIndex == value.length)) ? this
            : new String(value, beginIndex, subLen);
}

in this source (line 8~9), second parameter bigger than first parameter.

you will need to edit this.

String html = "This is a test string for example";
html.substring(html.indexOf("test"), (6+html.indexOf("test")));

hopefully, that will solve the problem.

Answer 2

Since the second parameter is an index, not the length, you need to store the initial position, and add the length to it, like this:

String html = "This is a test string for example";
int pos = html.indexOf("test");
String res = html.substring(pos, pos+11);

Demo.