I need to parse date value to specific format without using format field in dateFromString operator.
Mongo Playground
Current situation : in Mongodb 4.0 if I f
This worked for me: I used combined solution from @ambienBeing and @techstack. Thanks
Mongo playground
"parsedDate": {
"$dateFromParts": {
"year": {
"$year": {
$dateFromString: {
dateString: {
"$concat": [
"$_id.dateHour",
":00:00Z"
]
}
}
}
},
"month": {
"$month": {
$dateFromString: {
dateString: {
"$concat": [
"$_id.dateHour",
":00:00Z"
]
}
}
}
},
"day": {
"$dayOfMonth": {
$dateFromString: {
dateString: {
"$concat": [
"$_id.dateHour",
":00:00Z"
]
}
}
}
},
"hour": {
"$hour": {
$dateFromString: {
dateString: {
"$concat": [
"$_id.dateHour",
":00:00Z"
]
}
}
}
}
}
},
I think following query will solve your problem because MongoDB 3.6 supports dateFromString
Input:
[
{
"dateS": "2020-01-16T08"
}
]
Query:
db.collection.aggregate([
{
"$project": {
"year": {"$substr": ["$dateS",0,4]},
"month": {"$substr": ["$dateS",5,2]},
"day": {"$substr": ["$dateS",8,2]},
"hour": {"$substr": ["$dateS",11,2]}
}
},
{
$addFields: {
"isoString": {
"$concat": ["$year","-","$month","-","$day","T","$hour",":00:00Z"]
}
}
},
{
$addFields: {
"newDate": {
$dateFromString: {"dateString": "$isoString"}
}
}
}
])
Output:
[
{
"_id": ObjectId("5a934e000102030405000000"),
"day": "16",
"hour": "08",
"isoString": "2020-01-16T08:00:00Z",
"month": "01",
"newDate": ISODate("2020-01-16T08:00:00Z"),
"year": "2020"
}
]
If I get the requirement right, Try the following query which uses: $dateFromParts
Input:
[
{
"date": ISODate("2020-01-16T08:54:17.604Z")
}
]
Query:
db.collection.aggregate([
{
$project: {
outputDate: {
$dateFromParts: {
"year": {
$year: "$date"
},
"month": {
$month: "$date"
},
"day": {
$dayOfMonth: "$date"
},
"hour": {
$hour: "$date"
}
}
}
}
}
]);
O/P:
[
{
"_id": ObjectId("5a934e000102030405000000"),
"outputDate": ISODate("2020-01-16T08:00:00Z")
}
]
Playground Test Link