How can I do something like this.
index=[[test1,test2,test3],[test4,test5,test6],[test7,test8,test9]]
if test5 is in index:
print True
Using any + generator expression:
if any(test5 in subindex for subindex in index):
print True
Loop over your list of lists, and check for existence in each inner list:
for list in list_of_lists:
if needle in list :
print 'Found'
Or perhaps try itertools to unroll the array :-
index=[[test1,test2,test3],[test4,test5,test6],[test7,test8,test9]]
if test5 in itertools.chain(*index):
print True
try by this way
index = [['test1','test2','test3'], ['test4','test5','test6'], ['test7','test8','test9']]
any(filter(lambda x : 'test5' in x, index))
try
index=[[test1,test2,test3],[test4,test5,test6],[test7,test8,test9]]
flat_index=[item for sublist in index for item in sublist]
if test5 is in flat_index:
print True
see also Making a flat list out of list of lists in Python