I had core data storage, my field \"expensesAmount\" in Float identify. The value of expensesAmount is 6.3. But when I retrieve it to variable \"expensesAmount\" as below, it b
I think this is related to how the floating point numbers are expressed with IEEE-754 standard. With the standard, not all kinds of numbers with fraction may necessarily be expressed precisely even with double. This is irrelevant to Swift. The next small code in C will reproduce your issue.
int main(int argc, char **argv) {
float fval = 6.3f;
double dval = 6.3;
printf("%.10f : %.17f\n", fval, dval);
// 6.3000001907 : 6.29999999999999980
}
So, if you need the real accuracy in fractional part, you need to consider some other way.
EDITED: I checked with NSDecimalNumber and it's working as expected. Here is an example:
let bval = NSDecimalNumber(string: "6.3") // (1) 6.3
let bval10 = bval.multiplying(by: 10.0) // 63.0
let dval = bval.doubleValue
let dval10 = bval10.doubleValue
print(String(format: "%.17f", dval)) // 6.29999999999999982
print(String(format: "%.17f", dval10)) // (6) 63.00000000000000000
let bval2 = NSDecimalNumber(mantissa: 63, exponent: -1, isNegative: false)
print(bval2) // 6.3
let bval3 = NSDecimalNumber(mantissa: 123456789, exponent: -4, isNegative: true)
print(bval3) // -12345.6789
As you can see at (6), there's no round off when converting 6.3 at (1). Note 63.0 can be precisely expressed w/ float/double.
Try Follwoing :
let entity:NSManagedObject = data?.object(at: i) as! NSManagedObject
if let expensesAmount = entity.value(forKey: "expensesAmount") as? NSNumber {
totalAmount += expensesAmount.floatValue
}