I have a query that returns months 1-12. (INT)
Is there a way to order the results starting on this month desc?
Example
3
4
5
6
7
8
9
10
11
12
1
Much better in terms of execution cost:
Select * From
Group By monthcolumn,firstname,lastname
ORDER BY DATEPART(YEAR,datecolumn) DESC, DATEPART(MONTH, datecolumn) DESC
Or, this one is a little expensive in terms of execution cost:
Select * From
Group By monthcolumn ,firstname,lastname
ORDER BY CASE WHEN (DATEPART(MONTH, datecolumn))=3 THEN 1
WHEN (DATEPART(MONTH, datecolumn))=2 THEN 2
WHEN (DATEPART(MONTH, datecolumn))=1 THEN 3
WHEN (DATEPART(MONTH, datecolumn))=12 THEN 4
WHEN (DATEPART(MONTH, datecolumn))=11 THEN 5
WHEN (DATEPART(MONTH, datecolumn))=10 THEN 6
ELSE 0 END
ASC
Try simple maths in order by, if month is smaller then current add 12, not sure what will be the performance impact ...
Order By Case When month(dateColumn) < month(GetDate()) Then month(dateColumn) +12
ELSE month(dateColumn) END
Similar to Brad's answer, add a year column, then
...
ORDER BY year, month
Use ASCending or DESCending sort modifiers depending on exactly what you want to do.
You can add a year in there for sort purposes. Make them output something like:
2010-03
2010-04
...
2011-01
2011-02
Pseduo code:
WHERE year >= 2010 AND month >= 3
Not sure what your query is or the data backing it though.
Consider you have month column in your table with 1,2,3,---,11,12 values
SELECT *, case when `month`>=3 then `month`
else `month`+12 end as `temp_month`
FROM `tbl_name` order by `temp_month`
You will get output like
3
4
5
6
7
8
9
10
11
12
1
2
If you do not add years, it is impossible. The reasoning is because there is no way to tell which January or any month came first.
The only solution you have to to simply order them by YEAR
first, then by MONTH
.
So unless you change the field into a DATE
format or include a YEAR column, you can't do anything. Unless you want to arrange them by ID
; which was entered first.
So in short: No YEAR
= no way.