C++ - class issue

Question

At: http://www.learncpp.com/cpp-tutorial/82-classes-and-class-members/

There is the following program (I made some small modifications):

#include 

        

Answer 1

You'll have to include the header that declares the strncpy function. So add

#include <cstring> 

at the beginning.

And the member name is m_wage but you've used it as wage in your print member function.

Change

std::cout<<"Name: "<<m_strName<<"id: "<<m_id<<"wage: $"<<wage<<std::endl;

to

std::cout<<"Name: "<<m_strName<<"id: "<<m_id<<"wage: $"<<m_wage<<std::endl;
                                                         ^^^^^^

Answer 2

The error is because strncpy is declared in the cstring header file.

A pointer is used because you are working with C strings, which are char arrays. Arrays in C are used through pointers. And strncpy takes two pointers to char(char arrays) to do the copy process.

Answer 3

Regarding the last warning/error message - the first parameter of the setInfo() member function should be declared as const char*. Plain char* represents pointer to a mutable character array, which string literal "Abder-Rahman" isn't.

Answer 4

You need :

#include <string>
#include <iostream>
#include <string.h>

Answer 5

Add

#include <string.h>

And change wage to m_wage on line 19.

Answer 6

1.

strncpy(m_strName,strName,25);

You need to #include <cstring> (where strncpy is declared).

2.

std::cout<<"Name: "<<m_strName<<"id: "<<m_id<<"wage: $"<<wage<<std::endl;

should be

std::cout<<"Name: "<<m_strName<<"id: "<<m_id<<"wage: $"<<m_wage<<std::endl;

3.

void setInfo(char *strName,int id,double wage)

can be set to

void setInfo(const char *strName,int id,double wage)

to get rid of the g++ 4.x.x warning.