How to call a function 10 times like
for(x=0; x<10; x++) callfunction();
but with 1 sec between each call?
setInterval(function(){},1000);
Calls the function for every second...
You can also use setTimeout for your thing to work.
You can use setInterval for repeated execution with intervals and then clearInterval after 10 invocations:
callfunction();
var callCount = 1;
var repeater = setInterval(function () {
if (callCount < 10) {
callfunction();
callCount += 1;
} else {
clearInterval(repeater);
}
}, 1000);
Added: But if you don't know how long it takes your callfunction to execute and the accurate timings between invocation starting points are not important it seems it's better to use setTimeout for reasons mentioned by Paul S and those described in this article.
Similar to Amadan's answer but with a different style of closure which means you re-use instead of creating new functions
function call(fn, /* ms */ every, /* int */ times) {
var repeater = function () {
fn();
if (--times) window.setTimeout(repeater, every);
};
repeater(); // start loop
}
// use it
var i = 0;
call(function () {console.log(++i);}, 1e3, 10); // 1e3 is 1 second
// 1 to 10 gets logged over 10 seconds
In this example, if you were to set times
to either 0
or Infinity
, it would run forever.
function callNTimes(func, num, delay) {
if (!num) return;
func();
setTimeout(function() { callNTimes(func, num - 1, delay); }, delay);
}
callNTimes(callfunction, 10, 1000);
EDIT: The function basically says: make a call of the passed function, then after a bit, do it again 9 more times.
Another solution
for(var x=0; x<10; x++) window.setTimeout(callfunction, 1000 * x);
You can try to use setInterval
and use a variable to count up to 10. Try this:
var number = 1;
function oneSecond () {
if(number <= 10) {
// execute code here..
number++;
}
};
Now use the setInterval:
setInterval(oneSecond, 1000);