NSPredicate for exact match

Question

 NSArray *arrData = [NSArray arrayWithObjects:
                    @\"cloud,country,plant\",
                    @\"country,cloud,plant\",
                    @\"country         


        

Answer 1

Try:

 NSPredicate* predicate = [NSPredicate predicateWithBlock:^(NSString* string, NSDictionary* options){

    NSArray* array = [string componentsSeparatedByString:@","];

    return [array containsObject:@"cloud"];

}];

Answer 2

Try below code,

It will work,

 NSPredicate *hsPredicate = [NSPredicate predicateWithBlock:^BOOL(id  _Nonnull evaluatedObject, NSDictionary<NSString *,id> * _Nullable bindings) {
        NSArray *sepretArray =[((NSString*)evaluatedObject) componentsSeparatedByString:@","];
        NSPredicate *subPredicate = [NSPredicate predicateWithFormat:@"self == %@",@"cloud"];
        return  ([sepretArray filteredArrayUsingPredicate:subPredicate].count > 0);

    }];
    NSArray *arrResult = [arrData filteredArrayUsingPredicate:hsPredicate];

Answer 3

This one do the trick.But i don't know whether it is the efficient way of doing this.

 NSArray *arrData = [NSArray arrayWithObjects:
                    @"cloud,country,plant",
                    @"country,cloud,plant",
                    @"country,plant,cloud",
                    @"clouds,country,plant"
                    ,@"country,clouds,plant",
                    nil];

NSMutableArray *resArray = [[NSMutableArray alloc]init];
for(NSString *tempString in arrData)
{
    NSArray *cache = [tempString componentsSeparatedByString:@","];
    if([cache containsObject:@"cloud"])
      {
        [resArray addObject:tempString];
      }
}