Remove a tuple containing nan in list of tuples — Python

Question

I have a long list of tuples and want to remove any tuple that has a nan in it using Python.

What I currently have: x = [(\'Recording start\', 0), (nan, 4), (nan, 7

Answer 1

At least at my python usage of nan retured the 'not defined error', this is why I defined it by my self. I think you can use a Python filter function for yor needs. See the example:

nan = float('nan')
lst = [('Recording start', 0), (nan, 4), (nan, 7), ('Event marker 1', 150)]
y = filter( lambda x: nan not in x, lst)
print y

[('Recording start', 0), ('Event marker 1', 150)]

Answer 2

res = [n for n in x if not nan in n]

Return all objects in x that do not have an objects nan in them.

Answer 3

You could use list comprehension which checks if any of the items in a tuple is NaN. Check is done by first checking the type and then with math.isnan since it doesn't work for other types:

import math

x = [('Recording start', 0), (float('nan'), 4), (float('nan'), 7), ('Event marker 1', 150)]
res = [t for t in x if not any(isinstance(n, float) and math.isnan(n) for n in t)]
print(res)

Output:

[('Recording start', 0), ('Event marker 1', 150)]

Answer 4

Using list comprehension:

x = [('Recording start', 0), (nan, 4), (nan, 7), ('Event marker 1', 150)]

new = [i for i in x if nan not in i]